if x = 2t^2 + 4t find x ( 1) , x ( 0) also differentiate x
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Answer:
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Step-by-step explanation:
Explanation:
For parametric form of equation,
d
y
d
x
=
d
y
d
t
d
x
d
t
.
Here as
x
=
t
2
−
2
t
,
d
x
d
t
=
2
t
−
2
=
2
(
t
−
1
)
and as
y
=
t
4
−
4
t
,
d
y
d
t
=
4
t
3
−
4
=
4
(
t
3
−
1
)
=
4
(
t
−
1
)
(
t
2
+
t
+
1
)
Hence
d
y
d
x
=
4
(
t
−
1
)
(
t
2
+
t
+
1
)
2
(
t
−
1
)
=
2
(
t
2
+
t
+
1
)
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