If x 2x+2 3x+3 are in gp then the fourth term is
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In question
First term(a)=x
Common difference= 2x+2÷x
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Answer:
As we know
second term/first term=r
therefore
r=2x+2/x
so fourth term=third term x r
=(3x+3)(2x+2)/x
=6x^2+6x+6x+6/x
=6x^2+12x+6/x
=x(6x+12+6/x)/x
fourth term =6x+12+(6/x)
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