Question

If x, 2x+2, 3x+3 are the first three terms of a gp then what is its 4th term

Answer 1

The fourth term of the given GP would be 8(x+1)^3/x^2

1) Given first term of GP be x, second term be 2x+2 and third term be 3x+3.

2) In an Gp the ratio of subsequent terms remains same called the common ratio .

3) Here Common ratio s would be $\frac{2x+2}{x}$or 2+2/x

4) 4th term of a GP is given by ar^3

5) here a = x and r = 2+2/x.

6) So the 4th term would be x(2+2/x)^3 = 8(x+1)^3/x^2