if x+2y=1, 2x-3y=12 find the value of d
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Answer:
x+2y=1 ====> x+2y-1=0 .......(1)
2x-3y=21 =====> 2x-3y-21=0 .........(2)
Step-by-step explanation:
- multiply equation (1) with ×2
therefore {x+2y-1 ..... (1)} ×2 ----->
=2x+4y-2=0..... (3)
- subtract eqs. (3) from (2)
2x-3y-21=0
- 2x-4y-2=0
- + +
----------------
y-19=0
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therefore #y=19#
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if 2x-4y-2=0
2x-4 (19)-2=0
2x-76-2=0
2x-78=0
2x=78
x=78
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2
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#x=39#
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