Question

If (x + 2y – 1) (x + 3y - 3) = 1271, where x
and y are the natural numbers and (x + 2y
1), (x + 3y - 3) are the prime
numbers, then the value of is equal to
X​

Answer 1

Step-by-step explanation:

Given If (x + 2y – 1) (x + 3y - 3) = 1271, where x and y are the natural numbers and (x + 2y - 1), (x + 3y - 3) are the prime numbers, then the value of y/x is equal to

• Given condition is (x + 2y – 1) (x + 3y – 3) = 1271
• So we can write this as since both of them are prime numbers,
• (x + 2y – 1) (x + 3y – 3) = 31 x 41
• So x + 2y – 1 = 31
• And x + 3y – 3 = 41
• Solving both the equations we get
• Subtracting we get
• So – y + 2 = - 10
• Or – y = - 12
• Or y = 12
• So x + 2y – 1 = 31
• So x + 2(12) – 1 = 31
• So x + 23 = 31
• Or x = 8
• Now we need to find y/x = 12 / 8
• Or y/x = 3/2

Reference link will be

https://brainly.in/question/3438366