Math, asked by sskatsvs8105, 7 months ago

If (x + 2y – 1) (x + 3y – 3) = 1271, where x and y are the natural numbers and (x + 2y – 1), (x + 3y – 3) are the prime numbers, then the value of Y/X

Answers

Answered by chotabheem69
0

Step-by-step explanation:

Step-by-step explanation:

Given If (x + 2y – 1) (x + 3y - 3) = 1271, where x and y are the natural numbers and (x + 2y - 1), (x + 3y - 3) are the prime numbers, then the value of y/x is equal to

Given condition is (x + 2y – 1) (x + 3y – 3) = 1271

So we can write this as since both of them are prime numbers,

(x + 2y – 1) (x + 3y – 3) = 31 x 41

So x + 2y – 1 = 31

And x + 3y – 3 = 41

Solving both the equations we get

Subtracting we get

So – y + 2 = - 10

Or – y = - 12

Or y = 12

So x + 2y – 1 = 31

So x + 2(12) – 1 = 31

So x + 23 = 31

Or x = 8

Now we need to find y/x = 12 / 8

Or y/x = 3/2

Reference link will be

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