Math, asked by raahim, 1 year ago

if x-2y=11 and xy=8 find the value of x^3-8y^3

Answers

Answered by ARoy
189
x-2y=11
cubing both sides,
x³-8y³-3.x.2y(x-2y)=1331
or, x³-8y³-6.8.11=1331 [∵, xy=8 and x-2y=11]
or, x³-8y³=1331+528
or, x³-8y³=1859
Answered by EMPEROR72JAAT
30

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