Math, asked by Sapna1941, 1 year ago

if x-2y=11 and xy=8 find the value of x³-8y³

Answers

Answered by vaibhav789
40
x-2y=11
xy=8

 (x-2y)^3=x^3-8y^3-3xy(x-y)
=11^3=
x^3-8y^3-3x8x11
=1331=x^3-8y^3-264
=1331+264=x^3-8y^3
=1595=x^3-8y^3
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