Math, asked by manishaneerrohilla, 9 months ago

If x-2y = 11 xy=8 then find the value of x^2-8y^3​

Answers

Answered by Anonymous
0

Step-by-step explanation:

x-2y=11

cubing both sides,

x³-8y³-3.x.2y(x-2y)=1331

or, x³-8y³-6.8.11=1331 [∵, xy=8 and x-2y=11]

or, x³-8y³=1331+528

or, x³-8y³=1859

Answered by Anonymous
1

Answer:

the above answwer is correct points needed to me sorry for the answer ...

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