If x+2y=16 and 2x+y=11 then without finsing the values of x and y find the value of x+y
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x-2y-8=0
5x-10y=c

But if c = 40 (real value), then the ratio c1/c2 becomes 1/5 and then the system of linear equations has an infinitely many solutions.
Hence, ate = 40, the system of linear equations does not have a unique solution.
x-2y-8=0
5x-10y=c

But if c = 40 (real value), then the ratio c1/c2 becomes 1/5 and then the system of linear equations has an infinitely many solutions.
Hence, ate = 40, the system of linear equations does not have a unique solution.
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