Question

If (x - 2y +33)
(0-22+3x) (2 - 2x + 3y) and x + y +z
0
then prove that each ratio =
atbtc
2(x+y+z)​

Answer 1

Answer:

Solution :

$let \: \frac{a}{x - 2y + 3z} = \frac{b}{y - 2z + 3x} = \frac{c}{z - 2x + 3y} = k \\ by \: theoram \: of \: equal \: ratio \: \\ k = \frac{a + b + c}{x - 2y + 3z \ + y - 2z + 3x + z - 2x + 3y} \\ = \frac{a + b + c}{2x + 2y + 2z} \\ \frac{a + b + c}{2 \times x + y + z} \\ \frac{a}{x - 2y + 3z} = \frac{b}{y - 2z + 3x} = \frac{c}{z - 2x + 3y} = \frac{a + b + c}{2 \times x + y + z}$

Answer 2

Answer:

Step-by-step explanation: