Math, asked by stargirl0842006, 1 year ago

if x+2y+3z =0 then the value of x^3 +8y^3 +27z^3 is
answer with steps​

Answers

Answered by artistvikash1
7

Answer:

x+2y+3z=0

then

x^3+8y^3+27z^3 =3×x×2y×3z

=18xyz

ok

follow me

guys

Answered by aaravshrivastwa
19

As, Given

x+2y+3z=0

As we know that when,

a+b+c=0 then,

a³+b³+c³ = 3abc

x³ + 8y³ + 27z³ = 3.x.2y.3z

x³ + 8y³ + 27z³ = 18xyz.

Similar questions