Question

If x+2y+3z=6 and x -2y+z=8,then find value of x+4y+z

Answer 1

x + 4y + z = 5 If x + 2y + 3z = 6 and x-2y + z = 8,

Step-by-step explanation:

x + 2y + 3z = 6    Eq1

x-2y + z = 8         Eq2

Adding both Eq1 + Eq2

2x + 4z = 14

=> x + z = 7       Eq3

Eq1 - Eq2

4y  + 2z = -2

=> 2y + z  = -1       Eq4

Eq 3  + Eq 4

x + 2y + 2z = 6      Eq5

x + 2y + 3z   = 6   Eq 1

Equating Eq 5 & Eq 1

=> x + 2y + 2z =  x + 2y + 3z  

=> 2z = 3z

=> z = 0

x + z = 7    

=> x = 7

2y + z  = -1  

=> y = -1/2

x + 4y + z

= 7  + 4(-1/2) + 0

= 7 - 2

= 5

x + 4y + z = 5

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