Question

if x+2y=3z then x3 +8y3-27z3:xyz =
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Answer 1

Answer:

x+2y=3z

Cubing on both sides

(x+2y)³ = (3z)³

x³ + (2y)³ + 3(x)(2y)(x+2y) = 27x³

x³ + 8y³ + 6xy(3z) = 27x³

x³ + 8y³ -27x³ + 18xyz = 0

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Step-by-step explanation:

Answer 2

Answer:

(xyz)x+y+z=1 where xyz≠1andlog3(xyz)=−1, then logxyz(x3+y3+z3)equals=0