Math, asked by adilabbasi855pc5ntq, 1 year ago

if x=2y+6,find the value of ×^3-8y^3-36xy-216

Answers

Answered by gopika301
0
first substitute the value of x
(2y+6)^3-8y^3-36(2y+6)y-216
=8y^3+72y^2+216y+216-8y^3-72y^2-216y-216
=0
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