if x = 2y+6 find the value of x3 - 8y3 - 36xy -216
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Answered by
1
Answer:
2y+6=02y=-6y=-3than put value of x
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0
Answer:
so given
x = 2y+6
⇒ x - 2y = 6 ...... (i)
cubing both sides
⇒ x³ - 8y³ - 6xy(x - 2y) = 216
⇒ x³ - 8y³ - 6xy(6) = 216 {since , x - 2y = 6 from i}
⇒x³ - 8y³ - 36xy - 216 = 0
so the value of x³ - 8y³ - 36xy - 216 = 0 ANSWER
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