If x=2y+6,find the value of (x3-8y3-36xy-216).
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Answered by
24
F = x³ - 8 y³ - 36 x y - 216
x = 2 y + 6
F = 8 y³ + 216 + 72 y² + 216 y - 8 y³ - 72 y² -216 y - 216
= 0
x = 2 y + 6
F = 8 y³ + 216 + 72 y² + 216 y - 8 y³ - 72 y² -216 y - 216
= 0
Answered by
1
Answer:
F = x³ - 8 y³ - 36 x y - 216
x = 2 y + 6
F = 8 y³ + 216 + 72 y² + 216 y - 8 y³ - 72 y² -216 y - 216
= 0
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