Math, asked by reshva0nurain, 1 year ago

If x=2y+6,find the value of (x3-8y3-36xy-216).

Answers

Answered by kvnmurty
24
F = x³ - 8 y³ - 36 x y - 216
x = 2 y + 6

F = 8 y³ + 216 + 72 y² + 216 y - 8 y³ - 72 y² -216 y - 216
   = 0
Answered by smjothibasu
1

Answer:

F = x³ - 8 y³ - 36 x y - 216

x = 2 y + 6

F = 8 y³ + 216 + 72 y² + 216 y - 8 y³ - 72 y² -216 y - 216

  = 0

Similar questions