Question

if x+2y =8 and xy=2, find the value of x² +4y²​

Answer 1

Step-by-step explanation:

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Answer 2

x+2y=8

squaring on both sides

(x+2y)²=(8)²

by using a²+2ab+b²

a=x , b=2

x²+2.x.2y+2y²=64

x²+4xy+4y²=64

x²+4y²=64-4xy

x²+4y²=65-4×2

x²+4y²=64-8

x²+4y²=56

hope it helps you