if x+2y = 8 and xy= 6 find the value of x^3 + 8^3
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x + 2y = 8
xy = 6
y = 6/x
So x + 12/x = 8
x^2 - 8x + 12 = 0
(x-2)(x-6) = 0
So x=2 and y=3
(or)
x=6 and y=1
x^3 + 8y^3 = 8 + 8×27 = 224 (if x=2)
(or)
x^3 + 8y^3 = 216 + 8×1 = 224 (if x=6)
So final answer is 224.
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