If x +2y =9and xy =7 find the value of x square +4y square
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Squaring both sides :-
(x+2y)^2=9^2
x^2 +4xy +4y^2=81
x^2+4(7)+4y^2=81
x^2+28+4y^2=81
x^2+4y^2=81-28
x^2+4y^2=53
So value of (x+4y)^2=53
Hope it helps you and plz plz mark it as the brainlest answer..
(x+2y)^2=9^2
x^2 +4xy +4y^2=81
x^2+4(7)+4y^2=81
x^2+28+4y^2=81
x^2+4y^2=81-28
x^2+4y^2=53
So value of (x+4y)^2=53
Hope it helps you and plz plz mark it as the brainlest answer..
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