Question

If x-2y+k=0 is a midium of triangle whose verticles are A(-1,3) B(0,4) C (-5,2) , then find the value of k.

Answer 1

A (-1,3); B(0,4);C(-5,2)
x=(-1+0-5)/3=-2
y=(3+4+2)/3
x-2y+k=0
-2-2×3+ k=0
-2-6+k=0
-8+ k=0
k=8