Question

If x= √3+1/√3-1, and y=√3-1/√3+1 then the value of
x^2+ y^2\x^2 - y^2 is ​

Answer 1

So, (x + y)² = 4² = 16 and xy = (√3 + 1)/(√3 - 1) × (√3 - 1)/(√3 + 1) = (3 - 1)/(3 - 1) = 2/2 = 1 ∴ x² + y² + xy = (x + y)² ...