If x=√3+1/√3-1 and y=√3-1/√3+1 then value of (x²+y)
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Answer:
9+3√3
Step-by-step explanation:
x = √3 +1/ √3-1
rationalize denominatior
x = √3+1/√3-1. × (√3+1)/√3+1
x = (√3+1)^2/ (√3)^2 -1
x = 3 + 1 + 2√3/ 2
x= 4+2√3 / 2
x = 2 + √3
&
x^2 = (2+√3)^2
= 4 + 3 + 4√3
=. 7 + 4√3
then ,,, y = √3-1/3+1
rationalize denominatior
.
y = (√3-1)^2/ (√3)^2 -1
y = 3 + 1 -2√3 / 2
y = 4-2√3/ 2
y = 2-√3
then.......(x^2 +y)
= 7+4√3 + 2-√3
= 9 + 3√3 ✓✓✓✓✓✓
hope it's helpful (•‿•)(•‿•)(•‿•)
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