Math, asked by nicksshakya5951, 11 months ago

If x=√3+1/√3-1 and y=√3-1/√3+1 then value of (x²+y)

Answers

Answered by Anonymous
1

Answer:

9+3√3

Step-by-step explanation:

x = √3 +1/ √3-1

rationalize denominatior

x = √3+1/√3-1. × (√3+1)/√3+1

x = (√3+1)^2/ (√3)^2 -1

x = 3 + 1 + 2√3/ 2

x= 4+2√3 / 2

x = 2 + √3

&

x^2 = (2+√3)^2

= 4 + 3 + 4√3

=. 7 + 4√3

then ,,, y = √3-1/3+1

rationalize denominatior

.

y = (√3-1)^2/ (√3)^2 -1

y = 3 + 1 -2√3 / 2

y = 4-2√3/ 2

y = 2-√3

then.......(x^2 +y)

= 7+4√3 + 2-√3

= 9 + 3√3 ✓✓✓✓✓✓

hope it's helpful (•‿•)(•‿•)(•‿•)

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