If x=√3+1/√3-1 ,y=√3×1/√3+1 Find x+y?
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x+y = [(√3+1)(√3+1) - (√3-1)(√3-1)]/(√3-1)(√3+1)
= [3+1+2√3-3-1+2√3]/(3-1)
= [4√3]/2
= 2√3
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