Math, asked by makshayam1, 1 month ago

if x=√3+1/√3 and y=√3-1/√3 then x^2-y^2 is​

Answers

Answered by Anonymous
1

Answer:

» x² - y² = (x + y) (x - y)

= [ (√3 + 1)/√3 + (√3 - 1)/√3 ]

[ (√3 + 1)/√3 - (√3 - 1)√3 ]

= (2√3/√3) (2/√3)

= 4/√3

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