if x=√3+1/√3 and y=√3-1/√3 then x^2-y^2 is
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» x² - y² = (x + y) (x - y)
= [ (√3 + 1)/√3 + (√3 - 1)/√3 ]
[ (√3 + 1)/√3 - (√3 - 1)√3 ]
= (2√3/√3) (2/√3)
= 4/√3
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