Question

if x= 3^1/4 + 3^-1/4 and y =3^1/4 - 3^-1/4 then find the value of 3(x²+y²)²​

Answer 1

Step-by-step explanation:

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Answer 2

$Let \ a=3^{\frac14}\ and \ b=3^{-\frac14}\\\\Then \ 3 ( x^2+y^2)^2\\\\=3 [(a+b)^2+(a-b)^2]^2\\\\=3[a^2+b^2+2ab+a^2+b^2-2ab]^2\\\\=3[2(a^2+b^2)]^2\\\\=12( a^4+b^4+2a^2b^2)\\\\Putting \ the \ values \ of \ a \ and \ b \ we \ get\\\\=12[ (3^{\frac14})^4+(3^{-\frac14})^4+2(3^{\frac14}\times3^{-\frac14}) ]\\\\=12(3^1+3^{-1}+2)\\\\=12( 3+\frac13+2)\\\\=\frac{12}{3} (9+1+6)\\\\\bf =4\times16\\\\\\\bf =64$