Math, asked by tamimfamily53, 6 hours ago

if x= 3^1÷4+3^-1÷4, y=3^1÷4-3^-1÷4 then show that 3(x^2+y^2)=64

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Answered by dn4082746

Answer:

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Step-by-step explanation:

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if x= 3^1÷4+3^-1÷4, y=3^1÷4-3^-1÷4 then show that 3(x^2+y^2)=64​

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if x= 3^1÷4+3^-1÷4, y=3^1÷4-3^-1÷4 then show that 3(x^2+y^2)=64