Question

if (x/3 +1 ,y- 2/3)=(5/3 , 1/3) , find the value of x and y​

Answer 1

$\huge\mathfrak\pink{Answer}$

It is given that :-

$( \frac{x}{3} + 1,y - \frac{2}{3} ) = ( \frac{5}{3} , \frac{1}{3} )$

Since the ordered pairs are equal the corresponding element will also be equal

$therefore \: \frac{x}{3} + 1 = \frac{5}{3} \\ and \: \: \: \: = y - \frac{2}{3} = \frac{1}{3} \\ = y = 1 \\ = \frac{x}{3} + 1 = \frac{5}{3} \\ x = 2 \\ \\ ∴x = 2 \: and \: y = 1$

Hope it helps u ☺️

Answer 2

Answer:

• x = 2
• y = 1

Step-by-step explanation:

How to solve such questions?

Here equate the X-coordinate of LHS to X-coordinate of RHS and similarly equate Y-coordinate of LHS to Y-coordinate of RHS

SOLUTION:

• For X-coordinate;

$\pink{\tt{\dfrac{x}{3}+1=\dfrac{5}{3}}}$

Transpose 1 to RHS

$\dashrightarrow \: \: \tt{\dfrac{x}{3}=\dfrac{5}{3}-1}$

On taking LCM,

$\dashrightarrow \: \: \tt{\dfrac{x}{3}=\dfrac{5-3}{3}}$

Further simplifying,

$\dashrightarrow \: \: \tt{\dfrac{x}{3}=\dfrac{2}{3}}$

On Cancelling 3 in denominators,

$\therefore \boxed{\red{\bf{x=2}}}$

• For Y-coordinate;

$\green{\tt{y-\dfrac{2}{3}=\dfrac{1}{3}}}$

By Transposing,

$\Rightarrow \: \: \tt{y=\dfrac{1}{3}+\dfrac{2}{3}}$

$\Rightarrow \: \: \tt{y=\dfrac{3}{3}}$

$\therefore \boxed{\purple{\bf{y=1}}}$