If x (3/2)^2 *(2/3)^-4
Answers
Answered by
2
HEY!!
= (3/2)2*(3/2)4
Using the first law of exponents:-
am *an=a(m+n)
= (3/2)2*(3/2)4
= (3/2)2+4
= (3/2)6
Using the identity (a/b)m=(am/bm):-
= 36/26
= 729/64
= (3/2)2*(3/2)4
Using the first law of exponents:-
am *an=a(m+n)
= (3/2)2*(3/2)4
= (3/2)2+4
= (3/2)6
Using the identity (a/b)m=(am/bm):-
= 36/26
= 729/64
Answered by
8
Hi ,
*************************
We know the exponential laws
1 )( a/b )^ - n = ( b/a )^n
2 ) a^m × a^n = a^m + n
3 ) ( a/b )^m = a^m / b^m
****************************
Now ,
x = ( 3/2 )² ( 2/3 ) ^-4
= ( 3/2 )² ( 3/2 )⁴
= ( 3/2 )^ 2 + 4
= ( 3/2 )^6
= 3^6/ 2^6
= 729/64
I hope this helps you.
: )
*************************
We know the exponential laws
1 )( a/b )^ - n = ( b/a )^n
2 ) a^m × a^n = a^m + n
3 ) ( a/b )^m = a^m / b^m
****************************
Now ,
x = ( 3/2 )² ( 2/3 ) ^-4
= ( 3/2 )² ( 3/2 )⁴
= ( 3/2 )^ 2 + 4
= ( 3/2 )^6
= 3^6/ 2^6
= 729/64
I hope this helps you.
: )
Anonymous:
Thank you very much
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