if x=(3/2)^2×(2/3)^-4 find the value of x^-2?
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0
Answer:
1 )( a / b )^-n = ( b/a )^n
2 ) a^m × a^n = a ^m+n
3 ) ( a^m )^n = a^mn
x = ( 3/2 )^2 × ( 2/3 ) ^-4
x = ( 3/2 )² × ( 3/2 )⁴
x = ( 3/2 )^ 2 + 4
x = ( 3/2 )^6
x ^-2 = [ ( 3/2 )^6 ]^-2
= ( 3/2 ) ^ -12
= ( 2/3 )^12
Answered by
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Answer:
so,
If x=( 23 ) 2 ( 32 ) −4
=( 23 ) 2∗( 23 ) 4
=( 23 ) 6
so,
x −2
=( 23 ) −12
=( 32) 12
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