Math, asked by Chinnuthemaster, 16 days ago

if x=(3/2)^2×(2/3)^-4 find the value of x^-2?

Answers

Answered by shouryathakkar
0

Answer:

1 )( a / b )^-n = ( b/a )^n

2 ) a^m × a^n = a ^m+n

3 ) ( a^m )^n = a^mn

x = ( 3/2 )^2 × ( 2/3 ) ^-4

x = ( 3/2 )² × ( 3/2 )⁴

x = ( 3/2 )^ 2 + 4

x = ( 3/2 )^6

x ^-2 = [ ( 3/2 )^6 ]^-2

= ( 3/2 ) ^ -12

= ( 2/3 )^12

Answered by melasweertheart
0

Answer:

so,

If x=( 23 ) 2 ( 32 ) −4

=( 23 ) 2∗( 23 ) 4

=( 23 ) 6

so,

x −2

=( 23 ) −12

=( 32) 12

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