Math, asked by himanshusaxena1857, 9 months ago

if x = (3/2)^2 * (2/3)^-4, then find the value of x^-2.​

Answers

Answered by abhyudayVS
46

Answer:

(2/3)^12

Step-by-step explanation:

x=(3/2)^2*(2/3)^-4

x=(3/2)^2*(3/2)^4

x=(3/2)^6

(x)^-2={(3/2)^6}^-2. (both side multiplied by ^-2)

x^-2=(3/2)^-12

x^-2=(2/3)^12

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