Question

If x=(3/2)√2×(2/3)√-4find the value of x square

Answer 1

x=(3/2)√2×(2/3)√-4

x=(3√2/2)×(2√-4/3)

x= (3√2)(2)(2)(iota)/6

x= 12√2 iota/6

x= 2√2 iota

now find x^2

x^2 = (2√2 iota)^2

x^2 = 8 (iota)^2

x^2 = 8(-1)

x^2 = -8