Question

if x = 3 + 2√2 find, 1. 1/x 2. x-1/x 3. (x-1/x)^3 4. x^3 - 1/x^3​

Answer 1

Answer:

$x = 3 + 2 \sqrt{2}$

$1. \frac{1}{3 + 2 \sqrt{2} }$

$2. \frac{3 + 2 \sqrt{2} - 1}{3 + 2 \sqrt{2} } = \frac{2 + 2 \sqrt{2} }{3 + 2 \sqrt{2} }$

$3. ({ \frac{2 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } })^{3} = \frac{8 + 8 \sqrt{2} }{27 + 8 \sqrt{2} }$