Question

if x = 3+2√2, find 1) x+1/x 2) x-1/x

this is the question of 9 th standard plz answer correctly​

Answer 1

Step-by-step explanation:

Given,x=3-2√2

we have to find the value of x+(1/x)

taking 1 cm,

$x + (1 + x) = ( {x}^{2} + 1) \div x$

so,x+(1/x)=6.

for,

2. x-1/x is

x = 3 + 2√2

x = 3 + 2√2=> 1/x = 1/(3 + 2√2 )

x = 3 + 2√2=> 1/x = 1/(3 + 2√2 )=> 1/x = (3 - 2√2)/( (3 +2√2)*( 3 - 2√2) ) [ dividing and multiplying R.H.S. by (3 - 2√2) ]

x = 3 + 2√2=> 1/x = 1/(3 + 2√2 )=> 1/x = (3 - 2√2)/( (3 +2√2)*( 3 - 2√2) ) [ dividing and multiplying R.H.S. by (3 - 2√2) ]=> 1/x = (3–2√2)/(9–8) = 3 - 2√2

x = 3 + 2√2=> 1/x = 1/(3 + 2√2 )=> 1/x = (3 - 2√2)/( (3 +2√2)*( 3 - 2√2) ) [ dividing and multiplying R.H.S. by (3 - 2√2) ]=> 1/x = (3–2√2)/(9–8) = 3 - 2√2Now x - 1/x = (3 + 2√2) - ( 3 - 2√2) = 4√2

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