if x = 3 − 2√2, find the value of (x + 1/x )^2 . [use identity (a + b)^2 = a^2 + b^2+2ab]
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Answer:
X=3+2√2
x+¹/√x=?
x+¹/√x= (3+2√2)+1/(√3+2√2)
(√3+2√2 here means 3+2√2 whole root)
=(3+2√2)+(1)²/(√3+2√2)²
(squaring both numerator and dinominator)
=(3+2√2)+1/3+2√2
=(3+2√2)+1.(3-2√3)/(3+2√2)(3-2√2)
=(3+2√2)+(3-2√2)/3²-(2√2)²
=(3+2√2)+(3-2√2)/(9-8)
=3+2√2+3-2√2
=3+3
=6
Step-by-step explanation:
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