Question

if X=3+2√2, find the value of (√x-1/√x)​

Answer 1

$x = 3 + 2 \sqrt{2} \\ \frac{1}{x} = \frac{1}{3 + 2 \sqrt{2} } \\ \frac{1}{x} = \frac{1}{3 + 2 \sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ \frac{1}{x} = \frac{3 - 2 \sqrt{2} }{9 - 8} \\ \frac{1}{x} = 3 - 2 \sqrt{2} \\ \\ x + \frac{1}{x} = 6 \\ x + \frac{1}{x} - 2 = 4 \\ ( { \sqrt{x} - \frac{1}{ \sqrt{x} } })^{2} = 4 \\ \sqrt{x} - \frac{1}{ \sqrt{x} } = ±2$

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Answer 2

Answer:

Hope it helps you...↓↓↓

Step-by-step explanation:

•This evaluates to-

√2/1+√2

•The decimal form calculated to 10 digits is-

0.5857864376

•The rationalized form is-

√2×(√2-1)