Question

If X = 3 +2√2 find the value of x^2+ 1/x^2

Answer 1

X=3+(2*sqrt2)
1/X = 1/(3+(2*sqrt2))
Multiplying and dividing by 3-(2*sqrt2) we get 1/X=3-(2*sqrt2)
.......

Therefore X2 +1/X2 = 9+8+12sqrt2 +9+8-1]sqrt2..
= 34

Answer 2

Answer:

Given that,

x=3+2√2

then,

1/x= 1/(3+2√2)

=1/(3+2√2)*(3-2√2)/(3-2√2)

=(3-2√2)/(3^2-2√2^2)

=(3-2√2)/9-8

=3-2√2

according to the question

(x+1/x)^2 = x^2+1/x^2 + 2

(3+2√2+3-2√2) = x^2+1/x^2 + 2

6-2 = x^2+1/x^2

x^2+1/x^2 = 4

hope it will help