if x = 3-2√2 find the value of x^2-1/x^2
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x=(3-2√2)
1/x=1/(3-2√2)
=(3+2√2)/(3-2√2)(3+2√2)
=(3+2√2)/(3^2-2√2^2)
=(3+2√2)/(9-8)
=3+2√2
x^2-1/x^2
=(x+1/x)(x-1/x)
=(3-2√2+3+2√2)(3-2√2-3-2√2)
=6(-4√2)
= -24√2
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