if x= 3+2√2 , find x²+1/x²
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Answered by
3
Given x = 3 + 2√2
⇒ x2 = 17 + 12√2
⇒ 1/x2 = 1/(17 + 12√2)
On rationalizing the denominator we get
1/x2 = (17 – 12√2)
∴ (x2 +1/x2) =(17 + 12√2) + (17 – 12√2)
= 34
⇒ x2 = 17 + 12√2
⇒ 1/x2 = 1/(17 + 12√2)
On rationalizing the denominator we get
1/x2 = (17 – 12√2)
∴ (x2 +1/x2) =(17 + 12√2) + (17 – 12√2)
= 34
Tanvir913:
thanks bro
Answered by
1
x^2+ 1/x^2 = (3+2√2)^2+1/(3+2√2)2
(9+4×2)+1/(9+4×2)= 17+1/17 = 289+1/17=290/17=17.05
(9+4×2)+1/(9+4×2)= 17+1/17 = 289+1/17=290/17=17.05
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