Question

If x= 3_2√2 ,find xcube_1/x cube

Answer 1

Answer:

hey mate here is ur answer...

Answer 2

Answer:

-140√2

Step-by-step explanation:

x=3-2√2

1/x=1/3-2√2

=(3+2√2)/(3-2√2)(3+2√2)

=(3+2√2)/(9-8)

So 1/x =3+2√2---------------------------------(1)

============================

Now x³-1/x³

= (x-1/x) (x²+1/x²+x*1/x)

=[ (3-2√2)-(3+2√2)]  [x²+1/x²+2x*1/x-x*1/x ]

=( 3-2√2-3-2√2 ] [ (x+1/x)²-x*1/x]

=( -4√2 ] [ (3-2√2+3+2√2)² -1]

=(-4√2)[ 6²-1]

=-4*35√²

=-140√2