Question

if x = 3+2√2,them the value of x+1÷x is​

Answer 1

★Given :

x = 3+ 2√2

★ Solution :

$x = 3 + 2 \sqrt {2} \\ \\ or \: \: \frac{1}{x} = \frac{1}{3 + 2 \sqrt{2} } \\ \\ = \frac{3 - 2 \sqrt{2} }{(3 + 2 \sqrt{2})(3 - 2 \sqrt{2)} } \\ \\ = \frac{3 - 2 \sqrt{2} }{9 - 8} ( (x + y)(x - y) = {x}^{2} - {y}^{2} ) \\ \\ = 3 - 2 \sqrt{2}$

Therefore,

$x + \frac{1}{x} = 3 + 2 \sqrt{2} + 3 - 2 \sqrt{2} \\ \\ = 9$

Thanks :)

Answer 2

Step-by-step explanation:

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