if x = 3+2√2 then find the value of 1/x
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Answered by
2
Hey
Here is your answer,
Given that,
x = 3+2√2
1/x = 1/3+2√2
=1/3+2√3 x 3-2√2/3-2√2
=3-2√2/(3)^2 -(2√2)^2
=3-2√3 / 9-8
=3-2√3
Hope it helps you!
Here is your answer,
Given that,
x = 3+2√2
1/x = 1/3+2√2
=1/3+2√3 x 3-2√2/3-2√2
=3-2√2/(3)^2 -(2√2)^2
=3-2√3 / 9-8
=3-2√3
Hope it helps you!
StormBreaker:
acually the answer is 3-2√2 but i dont know how
Answered by
1
Hello Dear!!!
Here's your answer....
Given,
x = 3+2√2
then,
1/x is
1/(3+2√2)
rationalise the denominator
multiply the numerator and denominator with conjugate of denominator
denominator is 3+2√2
conjugate of 3+2√2 is 3-2√2
multiply....
1/(3+2√2) * (3-2√2)/(3-2√2)
3-2√2 / 9-8
3-2√2 / 1
3-2√2
3-2√2 is the answer.....
______________________________________
HOPE THIS HELPS YOU.....
Here's your answer....
Given,
x = 3+2√2
then,
1/x is
1/(3+2√2)
rationalise the denominator
multiply the numerator and denominator with conjugate of denominator
denominator is 3+2√2
conjugate of 3+2√2 is 3-2√2
multiply....
1/(3+2√2) * (3-2√2)/(3-2√2)
3-2√2 / 9-8
3-2√2 / 1
3-2√2
3-2√2 is the answer.....
______________________________________
HOPE THIS HELPS YOU.....
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