Question

if x=3+2√2 then find the value of x+1/×​

Answer 1

Answer:

the answer is ±2 ...

hope it's helpful for you

Answer 2

Hey mate!

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Given ;

$\rm{x = 3 + 2 \sqrt{2}}$

To find :

$\rm{x + \frac{1}{x}}$

Solution :

$\rm{x = 3 + 2 \sqrt{2} }\\ \\ \rm\frac{1}{x} = \frac{1}{3 + 2\sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ \\ \rm\frac{1}{x} = \frac{3 - \sqrt{2} }{(3) {}^{2} - (2 \sqrt{2}) {}^{2} } \\ \\ \rm\frac{1}{x} = \frac{3 - 2 \sqrt{2} }{9 - 8} \\ \\ \rm\frac{1}{x} = 3 - 2 \sqrt{2}$

Now

$\rm{x + \frac{1}{x}} \\ \\ \rm{ 3 + 2 \sqrt{2} + 3 - 2 \sqrt{2}} \\ \\ \rm{= 3 + 3} \\ \\ \rm \red{=6}$

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