Question

. If x = 3 + 2 √2, then find the value of (x + 1/x)​

Answer 1

Answer:

6

Step-by-step explanation:

$\text{given} \quad x = 3 + 2 \sqrt{2} \\ \\ \frac{1}{x} = \frac{1}{3 + 2 \sqrt{2} } \\ \\ = > \frac{1}{x} = \frac{1}{(3 + 2 \sqrt{2} )} \times \frac{(3 - 2 \sqrt{2}) }{(3 - 2 \sqrt{2}) } \\ \\ = > \frac{1}{x} = \frac{3 - 2 \sqrt{2} }{9 - 8} \\ \\ \frac{1}{x} = 3 - 2 \sqrt{2} \\ \\ now \\ \\ x + \frac{1}{x} \\ \\ = 3 + 2 \sqrt{2} + 3 - 2 \sqrt{2} \\ \\ = 6$

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Answer 2

Answer:

$givenx=3+22x1=3+221=>x1=(3+22)1×(3−22)(3−22)=>x1=9−83−22x1=3−22nowx+x1=3+22+3−22=6</p><p></p><p></p><p>$

Step-by-step explanation:

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