If x=3+2×√(2, then find the value of √(x - 1/√(x
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Solution:
x = 3+2√2 ----(1)
i ) √x = √3+2√2
= √2+1+2√2×√1
= √(√2)²+1²+2×√2×1
= √(√2+1)²
= √2 + 1 ----(2)
ii) 1/√x = 1/(√2+1)
Regionalizing the denominator, we get
= (√2-1)/[(√2+1)(√2-1)]
= (√2-1)/[(√2)²-1²]
= (√2-1)/(2-1)
= √2-1 ----(3)
Now ,
√x + 1/√x
= √2+1+√2-1
= 2√2
••••
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