If √x=3+2√2, then find the value of ( x-1/x) whole cube
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437+408root2/17+12root2 then just rationalise it
shivam884:
as x=(3+2root2)whole square then by this we get x=17+12root2 so x-1/x is given by 17+12root 2-1/17+12root 2
yeahh bro for sure❤
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I think by this you can do the sum
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is this answer correct
Yes
this is completely wrong answer because u have to apply (a+b)whole square identity here i.e a square+bsquare+2ab
u have not used 2ab
which makes this answer wrong
send me the question again
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