Math, asked by Vraj52, 1 year ago

if x=√3+√2/√3-√2 and x=√3-√2/√3+√2 find the value of x^2-y^2

Answers

Answered by aadithyakurup2005
0

Answer:

98

Step-by-step explanation:

answer will be 98

here x=√3+√2  / √3-√2

multiply numerator and denominator with   √3+√2

you will get x=5+2√6

find the square of x i.e x²

same way you find the value of y²

add them and you will get (49+20√6)+(49-20√6)=98

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