Question

If x = √3 + √2/ √3- √2 and y=1 the value of x-y/x-3y is (A) 5/√5-4 (B) 5/√6+4 (C) √6-4/5 (D) √6+4/5

Answer 1

option (d) is correct
Hope this helps you...✌

Answer 2

$x = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ x = \frac{( { \sqrt{3} + \sqrt{2} })^{2} }{3 - 2} \\ x = 5 + 2 \sqrt{6} \\ \\ y = 1 \\ \\ \frac{x - y}{x - 3y} = \frac{5 + 2 \sqrt{6} - 1}{5 + 2 \sqrt{6} - 3 } \\ = \frac{4 + 2 \sqrt{6} }{2 + 2 \sqrt{6} } \\ = \frac{2 + \sqrt{6} }{1 + \sqrt{6} } \\ = \frac{2 + \sqrt{6} }{1 + \sqrt{6} } \times \frac{1 - \sqrt{6} }{1 - \sqrt{6} } \\ = \frac{2 - 2 \sqrt{6} + \sqrt{6} - 6 }{1 - 6} \\ = \frac{ - 4 - \sqrt{6} }{ - 5} \\ = \frac{4 + \sqrt{6} }{5}$