Question

if x= √3 + √2/√3 - √2 and y= 1/x then x^2 + xy + y^2 find the value​

Answer 1

Step-by-step explanation:

$( \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } ) {}^{2} + \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{1}{x} + { \frac{1}{x} }^{2} \\ = \frac{5 + 2 \sqrt{6} }{5 - 2 \sqrt{6} } + \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3}x - \sqrt{2}x } + \frac{1}{ {x}^{2} }$

Its your answer