Question

If
=X
√3-√2/
√3+√2
and y =
√3+√2/
√3-√2 find the value of x square + y square + xy​

Answer 1

Answer:

step1:[√3-√2/√3+√2]*[√3-√2/√3+√2]+[√3+√2/√3-√2]*[√3+√2/√3-√2]+[√3-√2/√3+√2]*[√3+√2/√3-√2]

step2:[√3-√2/√3+√2]^2+[√3+√2/√3-√2]^2+[3-2/3-2]

step3:[5-2√6/5+2√6]+[5+2√6/5-2√6]+1

step4:[(5-2√6)*(5-2√6)+(5+2√6)*(5+2√6)/(25-24)]+1

step5:[25+24-4√6+25+24+4√6+1

step6:99